Home
Class 11
CHEMISTRY
The equilibrium constant of a reaction i...

The equilibrium constant of a reaction is 73. Calculate standard free energy change.

Text Solution

AI Generated Solution

To calculate the standard free energy change (ΔG°) for a reaction with an equilibrium constant (K) of 73, we can use the following formula: \[ \Delta G° = -2.303 \times R \times T \times \log K \] Where: - \( R \) is the universal gas constant, which is approximately \( 8.314 \, \text{J/(K·mol)} \). ...
Promotional Banner

Similar Questions

Explore conceptually related problems

If equilibrium constant for a reaction is K, then standard free energy change is :

The equilibrium constant of a reaction is 0.008 at 298 K . The standard free energy change of the reaction at the same temperture is

The equilibrium constant of a reaction and the standard Gibbs energy change of the reaction are related by the equation

The equilibrium constant of a reaction is 1xx10^(20) at 300 K . The standard free energy change for this reaction is :

If the equilibrium constant of a reaction is 2×10^3 at 25°C then the standard Gibbs free energy change for the reaction will be

Find the equilibrium constant K_(p) in log K_(p) if the standard free energy change of a reaction DeltaG^(@)=-115kJ at 298K is

The standard enthalpy or the decomposition of N_2 O_5 to NO_2 is 58.04 kJ and standard entropy of this reaction is 176.7 J/K. The standard free energy change for this reaction at 25^@ C is_____________.