Calculate the standard free energy change for the reaction,
`4NH_(3(g))+5O_(2(g))rarr4NO_((g))+6H_(2)O_((l))`. Given that the standard free energies of formation `(Delta_(f)G^(0))` for `NH_(3(g)),NO_((g))andH_(2)O_((l))` are - 16.8, + 86.7 and - 237.2 KJ `mol^(-1)` respectively. Predict the feasiblity of the above reaction at the standard state.

Explanation

To calculate the standard free energy change (ΔG°) for the reaction:

\[ 4NH_{3(g)} + 5O_{2(g)} \rightarrow 4NO_{(g)} + 6H_{2}O_{(l)} \]

we will use the formula for standard free energy change:

\[
\Delta G^{\circ} = \sum (\Delta_f G^{\circ} \text{ of products}) - \sum (\Delta_f G^{\circ} \text{ of reactants})
...