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H(2) (g) +I(2) (g) rarr 2HI (g), DeltaH=...

`H_(2) (g) +I_(2) (g) rarr 2HI (g), DeltaH=51.9 kJ`.
According to this, heat of formation of `HI` is

A

51.9 KJ

B

`-51.9` KJ

C

`-25.95` KJ

D

25.95 KJ

Text Solution

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The correct Answer is:
D
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