Home
Class 11
CHEMISTRY
DeltaH (vap) for water is 40.7 kJ mol^(-...

`DeltaH` (vap) for water is `40.7 kJ mol^(-1)`. The entropy of vapourisation of water is

A

`-40.7KJmol^(-1)`

B

`407Jmol^(-1)K^(-1)`

C

`109Jmol^(-1)k^(-1)`

D

`722Jmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`DeltaS=(DeltaH)/(T)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Standard enthalpy of vapourisation DeltaH^(@) forwater is 40.66 KJ mol^(-1) .The internal energy of vapourisation of water for its 2 mol will be :-

The standard enthalpy change for the transition of liquid water of steam is 40.8 kJ mol^(-1) at 373 K. Calculate the entropy of vaporisation of water.

Standard enthalpy of vaporisation DeltaV_(vap).H^(Theta) for water at 100^(@)C is 40.66kJmol^(-1) .Teh internal energy of Vaporization of water at 100^(@)C("in kJ mol"^(-1)) is

If the enthalpy of vaporization for water is 198.5KJ mol^(-1) , the entropy of its vaprization will be

Enthalpy of vapourisation for water is 186.5 KJ "mole"^(-1) . The entropy change during vapourisation is ______ KJ "mole"^(-1)