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CO((g))+1/2 O(2) (g) rarr CO(2(g)) Del...

`CO_((g))+1/2 O_(2) (g) rarr CO_(2(g))`
`DeltaH=-67.37` K.cal at `25^(@)C` the change in entropy accompanying process is `-20.7` cal.`deg^(-1) mol^(-1)` then at `25^(@)C` the change in free energy is

A

`-10K.calmol^(-1)`

B

`-15K.cal."mole"^(-1)`

C

`-32K.cal mol^(-1)`

D

`-61.2K.calmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG=DeltaH-TDeltaS`
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