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Heat capacity (C(V)) of an ideal gas is ...

Heat capacity `(C_(V))` of an ideal gas is X KJ/mole/K. To rise its temperature from 298 K to 318 K, heat to be supplied per 10g gas will be (in KJ) [MW = 16]

A

16X

B

6.25X

C

32X

D

12.5X

Text Solution

Verified by Experts

The correct Answer is:
D
`C=(q)/(T_(2)-T_(1))C_(V)` for 1 mole 16 gm `rarr` x KJ
`10gmrarr?(10x)/(16),(10x)/(16)rarr1^(@)C`
`?rarr20^(@)C`
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