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S(H(2(g)))^(0) = 130.6 J K^(-1) mol^(-1)...

`S_(H_(2(g)))^(0) = 130.6 J K^(-1) mol^(-1)`, `S_(H_(2)O_((l)))^(0)= 69.9 J K^(-1)mol^(-1)`
`S_(O_(2(g)))^(0) = 205 J K^(-1)mol^(-1)`, then the absolute entropy change of `H_(2_((g))) + (1)/(2)O_(2_((g))) rarr H_(2)O_((l))` is

A

`-163.2Jmol^(-1)K^(-1)`

B

`+163.2Jmol^(-1)K^(-1)`

C

`-303Jmol^(-1)K^(-1)`

D

`+303Jmol^(-1)K^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaS=S_(P)-S_(R)`
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