Home
Class 11
CHEMISTRY
Calculate the change in enthalpy for the...

Calculate the change in enthalpy for the following process at 1 atm
`H_(2)O(1, 50^(@)C) rarr H_(2)O (g, 150^(@)C)` given that `Delta H_(v)` at `100^(@)C` is `40.7 kJ mol^(-1)`
`C_(p)(H_(2)O, l) = 75.0 J mol^(-1)K^(-1)`
`C_(p)(H_(2)O, g) = 33.3 J mol^(-1)K^(-1)`

A

64.8 KJ

B

52.4 KJ

C

48.6 KJ

D

46.1 KJ

Text Solution

Verified by Experts

The correct Answer is:
D

`H_(2)0_((l))(50^(@)C)rarrH_(2)O_((l))(100^(@)C)rarrH_(2)O_((g))(150^(@)C)`
`DeltaH=DeltaH_(1)+DeltaH_(2)+DeltaH_(3)C_(P)=(DeltaH)/(T)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Predict the standard reaction enthalpy of 2NO_(2)(g)rarrN_(2)O_(4)(g) at 100^(@)C . Delta H^(@) at 25^(@)C is -57.2 kj.mol^(-1)C_(p)(NO_(2))=37.2j.mol^(-1)K^(-1)C_(p)(N_(2)O_(4))=77.28 J. mol^(-1)k^(-1)

Calculated the equilibrium constant for the following reaction at 298K : 2H_(2)O(l) rarr 2H_(2)(g) +O_(2)(g) Delta_(f)G^(Theta) (H_(2)O) =- 237.2 kJ mol^(-1),R = 8.314 J mol^(-1) K^(-1)

Calcualte the enthalpy change on freezing of 1.0 mole of water at 10.0^(@)C to ice at -10^(@) C. Delta_(fs)H=6.03 kJ mol^(-1) at 0^(@)C . C_(p)[H_(2)O(l)] = 75.3 J mol^(-1) K^(-1), C_(P)[H_(2)O(s)] = 36.8 Jmol^(-1)K^(-1)

Calculate the entropy change accompanying the following change of state H_(2)O (s, 10^(@)C, 1 atm) rarr H_(2)O(l, 10^(@)C, 1atm) C_(P) for ice = 9 cla deg^(-1) mol^(-1) C_(P) for H_(2)O = 18 cal deg^(-1) mol^(-1) Latent heat of fustion of ice = 1440 cal mol^(-1) at 0^(@)C .

Calculate the equilibrium constant for the following reaction at 298K and 1 atmospheric pressure: C(graphite) +H_(2)O(l) rarr CO(g) +H_(2)(g) Given Delta_(f)H^(Theta) at 298 K for H_(2)O(l) =- 286.0 kJ mol^(-1) for CO(g) =- 110.5 kJ mol^(-1) DeltaS^(Theta) at 298K for the reaction = 252.6 J K^(-1) mol^(-1)

Calculate the standard enthalpy of formation of CH_(3)OH(l) from the following data: CH_(3)OH(l)+3/2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l), …(i), Delta_(r)H_(1)^(Θ)=-726 kJ mol^(-1) C(g)+O_(2)(g) rarr CO_(2)(g), …(ii), Delta_(c )H_(2)^(Θ)=-393 kJ mol^(-1) H_(2)(g)+1/2O_(2)(g) rarr H_(2)O(l), ...(iii), Delta_(f)H_(3)^(Θ)=-286 kJ mol^(-1)

Calculate the resonance enegry of toulene (use Kekule structure form the following data C_(7)H_(8)(l) +9O_(2)(g) rarr 7CO_(2)(g) +4H_(2)O(l)+ DeltaH, DeltaH^(Theta) =- 3910 kJ mol^(-1) C_(7)H_(8)(l) rarr C_(7)H_(8)(g), DeltaH^(Theta) = 38.1 kJ mol^(-1) Delta_(f)H^(Theta) (water) =- 285.8 kJ mol^(-1) Delta_(f)H^(Theta) [CO_(2)(g)] =- 393.5 kJ mol^(-1) Heat of atomisaiton of H_(2)(g) = 436.0 kJ mol^(-1) Heat of sulimation of C(g) = 715.0 kJ mol^(-1) Bond energies of C-H, C-C , and C=C are 413.0, 345.6 , and 610.0 kJ mol^(-1) .