Given the enthalpy of formation of CO(2)...

Given the enthalpy of formation of `CO_(2)(g)` is -94.0 KJ, of CaO(s) is -152 KJ, and the enthalpy of the reaction `CaCO_(3)(s) rarr CaO(s)+CO_(2)(g)` is 42KJ, the enthalpy of formation of `CaCO_(3) (s)` is

A

`-268KJ`

B

`+202KJ`

C

`-202KJ`

D

`-288KJ`

Verified by Experts

The correct Answer is:

D

`CaCO_(3)rarrCaO+CO_(2),DeltaH=H_(P)-H_(R)`

Similar Questions

Explore conceptually related problems

For the reaction : CaCO_(3) (s) hArr CaO (s) + CO_(2) (g)

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

Given ehthapy of formation of CO_2(g) and CaO(s) are -94.0 kJ and -152 kJ respectively and the enthalpy of formation CaCO_3(s) is

For the reaction, CaCO_(3)(s) rarr CaO(s)+CO_(2)(g) , which is the correct representation?

The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when

Write the expression K_p for the reaction : CaCO_3(s) hArr CaO(s) +CO_2(g)

which is correct about the following reaction ? CaCO_(3)(s) hArr CaO(s) +CO_(2)(g)

Write the expression for K_p for the reaction: CaCO_3(s) hArr CaO(s) +CO_2(g)