H(2)O((g))rarrH((g))+OH((g))DeltaH=x(1),...

`H_(2)O_((g))rarrH_((g))+OH_((g))DeltaH=x_(1)`,
`OH_((g))rarrH_((g))+O_((g))DeltaH=x_(2)`
Based on these value, BE of O-H bond is

A

`(x_(1)+x_(2))/(2)`

B

`x_(1)+x_(2)`

C

`(x_(1)-x_(2))/(2)`

D

`2(x_(1)+x_(2))`

Text Solution

Verified by Experts

The correct Answer is:

A

`DeltaH=H_(R)-H_(P)`

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