Home
Class 11
CHEMISTRY
Calculate the free energy change for the...

Calculate the free energy change for the following reaction at 300 K.
`2CuO_((s)) rarr Cu_(2)O_((s))+(1)/(2)O_(2(g))` Given `Delta H = 145.6 kJ mol^(-1)` and `Delta S = 116.JK^(-1) mol^(-1)`

A

`110.8kJmol^(-1)`

B

`221.5kJmol^(-1)`

C

`55.4kJmol^(-1)`

D

`145.6kJmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG=DeltaH-TDeltaS`
Promotional Banner

Similar Questions

Explore conceptually related problems

Predict whether the following reaction is possible or not at 300k . 2CuO(s) rarr Cu_(2)O(s) +1//2O_(2)(g) DeltaH =- 144.6 kJ mol^(-1), DeltaS = 0.116 kJ mol^(-1)

Calculate the temperature above which the reaction of lead oxide to lead in the following reaction become spontaneous. PbO(s) + C(s) rarr Pb(s) + CO(g) Given Delta H = 108.4 kJ mol^(-1), Delta S = 190 JK^(-1) mol^(-1)

Calculate the standard free energy change for the reaction: H_(2)(g) +I_(2)(g) rarr 2HI(g), DeltaH^(Theta) = 51.9 kJ mol^(-1) Given: S^(Theta) (H_(2)) = 130.6 J K^(-1) mol^(-1) , S^(Theta) (I_(2)) = 116.7 J K^(-1) mol^(-1) and S^(Theta) (HI) =- 206.8 J K^(-1) mol^(-1) .

Calculate the standard free energy change for the reaction : H_(2)(g) + I_(2)(g) to 2HI(g) DeltaH^(@) = 51.9 kJ "mol"^(-1) Given : S^(@)(H_(2)) = 130.6 J K^(-1) "mol"^(-1) S^(@)(I_(2)) = 116.7 J K^(-1) "mol"^(-1) and S^(@)(HI) = 206.3 J K^(-1) "mol"^(-1) .

Calculated the equilibrium constant for the following reaction at 298K : 2H_(2)O(l) rarr 2H_(2)(g) +O_(2)(g) Delta_(f)G^(Theta) (H_(2)O) =- 237.2 kJ mol^(-1),R = 8.314 J mol^(-1) K^(-1)

Calculate the temperature above which the reduction of lead oxide to lead in the following reaction become spontaneous. PbO(s) + C(s) rightarrow Pb(s) + CO(g) Given Delta H = 118.4 kJ mol^(-1), Delta S = 200 JK^(-1) mol^(-1) .

The temperature at which the given reaction is at equilibrium Ag_(2)O_(s) rightarrow 2Ag(s) + 1/2 O_(2)(g) Delta H = 40.5 kJ mol^(-1) and DeltaS= 0.086 k J mol^(-1) K^(-1)

Calculate the change in entropy for the following reaction 2CO(g) +O_(2)(g) rarr 2CO_(2)(g) Given: S_(CO)^(Theta)(g)=197.6 J K^(-1)mol^(-1) S_(O_(2))^(Theta)(g)=205.03 J K^(-1)mol^(-1) S_(CO_(2))^(Theta)(g)=213.6 J K^(-1)mol^(-1)