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The lattice energy of solid NACl is 180K...

The lattice energy of solid `NACl` is `180K. Cal mol^(-1)`. The dissolution of the solid in water in the form of ions is endothermic to the extent of `1 K.cal mol^(-1)`. If the hydration energies of `NA^(+)` and `Cl^(-)` are in ratio `6 : 5`, what is the enthalpy of hydration of `NA^(+)` ion

A

`-85.6K.calmol^(-1)`

B

`-97.5K.calmol^(-1)`

C

`-182.6K.calmol^(-1)`

D

`+100K.calmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH_(sol^(n))=DeltaH_(L.E)+DeltaH_(H.E)`
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