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The standard Gibb's energy change for th...

The standard Gibb's energy change for the formation of propane. `C_(3)H_(8) (g)` at 298 K is
`[Delta_(f)H^(theta)` for propane `=-103.85 kJ" mole"^(-1), S^(theta)._(m)C_(3)H_(8)(g)=270.2J.K^(-1) mol^(-1), S^(theta)._(m)H_(2)(g)=130.68J.K^(-1) mol^(-1)`. and `S^(theta)._(m)C_("(graphite)")=5.74JK^(-1) mol^(-1)]`

A

`-23.4K.J`

B

`-44.4K.J`

C

`-54.4K.J`

D

`-104.5KJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG^(0)=DeltaH^(0)-TDeltaS^(0)`
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