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At 60^(@) and 1 atm, N(2)O(4) is 50% dis...

At `60^(@)` and 1 atm, `N_(2)O_(4)` is `50%` dissociated into `NO_(2)` then `K_(p)` is

A

`-863.8Jmol^(-1)`

B

`-963.8Jmol^(-1)`

C

`-973.8Jmol^(-1)`

D

`-796.9Jmol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(2)O_(4)iff2NO_(2)`
`{:(1,0),(1-0.5,2xx0.5):}`
Total Moles = `1.5,DeltaG^(0)=-2.303RTlogK_(p)`
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