The standard Gibb's energy change for the formation of propane. `C_(3)H_(8) (g)` at 298 K is
`[Delta_(f)H^(theta)` for propane `=-103.85 kJ" mole"^(-1), S^(theta)._(m)C_(3)H_(8)(g)=270.2J.K^(-1) mol^(-1), S^(theta)._(m)H_(2)(g)=130.68J.K^(-1) mol^(-1)`. and `S^(theta)._(m)C_("(graphite)")=5.74JK^(-1) mol^(-1)]`

Options

A. `-23.4K.J`
B. `-44.4K.J`
C. `-54.4K.J`
D. `-104.5KJ`

Answer

A

Explanation

`DeltaG^(0)=DeltaH^(0)-TDeltaS^(0)`