Two liquids `A` and `B` have `P_(A)^(@)` and `P_(B)^(@)` in the ratio of `1:3` and the ratio of number of moles of `A` and `B` in liquid phase are `1:3` then mole fraction of `A` in vapour phase in equilibrium with the solution is equal to :

Two liquids A and B have P_(A)^(0):P_(B)^(0)=1:3 at a certain temperature. If the mole fraction ratio of x_(A) : x_(B) = 1:3 , the mole fraction of A in vapour in equilibrium with the solution at a given temperature is :

If two substances A and B have p_(A)^(@): p_(B)^(@) = 1:2 and have mole fraction in solution as 1:2 then mole fraction of A in vapour phase is

If two substances A and B have p_(A)^(@): p_(B)^(@) = 1:2 and have mole fraction in solution as 1:2 then mole fraction of A in vapour phase is

For an ideal binary liquid solutions with P_(A)^(@)gtP_(B)^(@) , which relation between X_(A) (mole fraction of A in liquid phase) and Y_(A) (mole fraction of A in vapour phase) is correct:

For an ideal binary liquid solutions with P_(A)^(@)gtP_(B)^(@) , which relation between X_(A) (mole fraction of A in liquid phase) and Y_(A) (mole fraction of A in vapour phase) is correct:

Two liquids A and B have vapour pressure in the ratio P_A^@:P_B^@ =2:3 at a certain temperature. Assume A and B form an ideal solution and the ratio of mole fractions of A to B in the vapour phase in 1:3,then the mole fraction of A in the solution at the same temperature is :

Two liquids A and B form an ideal solution. The ratio of vapour pressures of pure liquids A and B are 3: 5. If the mole fraction of A in the liquid solution at equilibrium with vapours is 0.4, then the mole-fraction of B in the liquid is