If the cell of an organism heterozygous for three pairs of genes represented by AaBbCc, undergoes meiosis then possible type of gametes will be :-

Options

A. 4
B. 2
C. 8
D. 12

Answer

To solve the problem of determining the possible types of gametes produced by a cell heterozygous for three pairs of genes (AaBbCc) undergoing meiosis, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Genes and Their Alleles**:
- The organism is heterozygous for three pairs of genes: A/a, B/b, and C/c.
- This means the alleles for each gene are:
- Gene A: A (dominant) and a (recessive)
- Gene B: B (dominant) and b (recessive)
- Gene C: C (dominant) and c (recessive)

2. **Use the Formula for Gamete Calculation**:
- To find the number of possible gametes, we use the formula \(2^n\), where \(n\) is the number of heterozygous gene pairs.
- In this case, there are 3 pairs of genes (A/a, B/b, C/c), so \(n = 3\).

3. **Calculate the Number of Gametes**:
- Plugging in the value of \(n\) into the formula gives:
\[ 2^3 = 8 \]
- Therefore, there will be 8 possible types of gametes.

4. **List the Possible Gametes**:
- The possible combinations of alleles from the three gene pairs can be determined by listing them:
- ABC
- ABc
- AbC
- Abc
- aBC
- aBc
- abC
- abc
- Each combination represents a unique gamete.

5. **Conclusion**:
- The possible types of gametes produced are: ABC, ABc, AbC, Abc, aBC, aBc, abC, and abc.

### Final Answer:
The possible types of gametes produced by the organism heterozygous for three pairs of genes (AaBbCc) undergoing meiosis are 8: ABC, ABc, AbC, Abc, aBC, aBc, abC, and abc.

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