A dihybrid plant with incomplete linkage on test corss may produce how many types of plants :-

Options

A. 2
B. 4
C. 8
D. 1

Answer

To solve the question regarding how many types of plants a dihybrid plant with incomplete linkage may produce on a test cross, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Dihybrid Cross**:
A dihybrid cross involves two traits, each represented by two alleles. For example, we can consider a plant with the traits for height (Tall 'T' and short 't') and seed shape (Round 'R' and wrinkled 'r').

2. **Identify the Genotypes**:
In this case, we have a dihybrid plant that is heterozygous for both traits (TtRr). We will cross this plant with a homozygous recessive plant (ttrr).

3. **Determine Gamete Formation**:
The dihybrid plant (TtRr) can produce four types of gametes due to independent assortment:
- TR
- Tr
- tR
- tr

4. **Perform the Test Cross**:
The test cross involves crossing the dihybrid plant (TtRr) with the homozygous recessive plant (ttrr). The possible combinations of gametes from both parents will lead to the following offspring:
- TR (from TtRr) with tr (from ttrr) → TtRr (Tall, Round)
- Tr (from TtRr) with tr (from ttrr) → Ttrr (Tall, Wrinkled)
- tR (from TtRr) with tr (from ttrr) → ttRr (Short, Round)
- tr (from TtRr) with tr (from ttrr) → ttrr (Short, Wrinkled)

5. **Count the Offspring Types**:
From the combinations above, we can see that there are four distinct phenotypes produced:
- Tall, Round
- Tall, Wrinkled
- Short, Round
- Short, Wrinkled

6. **Conclusion**:
Therefore, a dihybrid plant with incomplete linkage on a test cross may produce **4 types of plants**.

### Final Answer:
The answer is **4 types of plants**.

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