Base ratio of a DNA is `0.03` and the amount of `A-TN_(2)` base contents is 30000, then what is the amount of `G-C,N_(2)` bae contents in this DNA?

Options

A. 1000
B. 10000
C. 100000
D. None

Answer

To solve the problem, we need to find the amount of G-C base contents in the DNA given the base ratio and the amount of A-T base contents.

### Step-by-Step Solution:

1. **Understand the Base Ratio**: The base ratio is defined as the ratio of the sum of adenine (A) and thymine (T) to the sum of guanine (G) and cytosine (C). In mathematical terms, it can be expressed as:
\[ \text{Base Ratio} = \frac{A + T}{G + C} \]

2. **Substitute the Given Values**: We are given that the base ratio is 0.03 and the amount of A + T is 30,000. We can substitute these values into the equation:
\[ 0.03 = \frac{30,000}{G + C} \]

3. **Rearrange the Equation**: To find \( G + C \), we can rearrange the equation:
\[ G + C = \frac{30,000}{0.03} \]

4. **Calculate \( G + C \)**: Now, we perform the calculation:
\[ G + C = \frac{30,000}{0.03} = 1,000,000 \]

5. **Conclusion**: The amount of G-C base contents in this DNA is 1,000,000.

### Final Answer:
The amount of G-C base contents in the DNA is **1,000,000**.

---