First and second ionisation energies of magnesium are `7.646 eV` and `15.035ev` respectively. The amount of energy in `kJ` needed to convert all the atoms of magnesium intp `Mg^(2+)` ions present in `12 mg` of magnesium vapour will be? [Given `1 eV = 96.5 kJ ml^(-1)]`

First and second ionisation energies of magnesium are 7.646 ev and 15.035 eV respectively what will be the amount of energy in Kj needed to convert all the atoms of magnesium into Mg^(2+) ions present in 12 mg of magnesium vapour?

First and second ionisation energies of magnesium are 5.7 and 15.035eV respectively. The amount of energy in kJ needed to convert all the atoms of magnesium into Mg^(+2) ions present in 12mg of magnesium vapour is [1eV=96.5kJ " mol"^(-1) ]

First and second ionization energies of magnesium are 7.646 and 15.035 eV respectively. The amount of energy in kJ/mol needed to convert all the atoms of Magnesium into Mg^(2+) ions present in 12 mg of magnesium vapours is: (Report your answer by multiplying with 10 and round it upto nearest integer) (Given 1 eV = 96.5 kJ mol^(-1))

First and second ionization energies of magnesium are 7.646 and 15.035 eV respectively. The amount of energy in kJ/mol needed to convert all the atoms of Magnesium into Mg^(2+) ions present in 12 mg of magnesium vapours is: (Report your answer by multiplying with 10 and round it upto nearest integer) (Given 1 eV = 96.5 kJ mol^(-1))

How much energy in joules must be needed to convert all the atoms of sodium to sodium ions present in 4.6 mg of sodium vapours? Ionization enthalpy of sodium is 495 "kJ mol"^(-1)

How much energy in joules must be needed to convert all the atoms of sodium to sodium ions present in 4.6 mg of sodium vapours? Ionization enthalpy of sodium is 495 "kJ mol"^(-1)

The first second and third ionisation energies of AI are 587 , 1817 and 2745 kJ "mol"^(-1) respectively . Calculate the energy required to convert all the atoms of AI to AI^(+3) present in 270 mg of AI vapours

The first second and third ionisation energies of AI are 587 , 1817 and 2745 kJ "mol"^(-1) respectively . Calculate the energy required to convert all the atoms of AI to AI^(+3) present in 270 mg of AI vapours