[" 6.In Fig."6.37" ,if "Delta ABE~=Delta ACD" ,show that "],[Delta ADE sim Delta ABC" ."]

In Fig. 6.37, if Delta ABE~=Delta ACD , show that Delta ADE~Delta ABC .

In that figure, if Delta ABE ~= Delta ACD , show that Delta ADE ~= Delta ABC .

In Fig. If Delta ABE = ACD , show that Delta ADE ~ Delta ABC .

In Delta ABC , AB = AC and BC = 6cm, D is a point on the side AC such that AD = 5cm and CD = 4cm, show that Delta BCD ~ Delta ABC and hence find DB .

In Fig.9.23,E is any point on median AD of a Delta ABC Show that ar (ABE)=ar(ACE)

The given figure shows two isosceles triangles ABC and DBC with common base BC. AD is extended to intersect BC at point P. Show that: Delta ABD = Delta ACD (ii) Delta ABP = Delta ACP (iii) AP bisects angle BDC (iv) AP is perpendicular bisector of BC.

In the adjoining figure,E is a point on the median AD of a Delta ABC. Show that ar (Delta ABE)=(Delta ACE)

S and T are points on sides PR and QR of Delta PQR such that /_P=/_RTS Show that Delta RPQ sim Delta RTS

In a triangle ABC, AB = AC. Show that the altitude AD is median also.

ABC is a triangle in which altitude BE and CF to sides AC and AB are equal. Show that Delta ABE ~= Delta ACF (ii) AB = AC, i.e., ABC is an isosceles triangle.