(ii)(cos^(2)25^(@)+cos^(2)65^(@))+cosec theta sec(90^(@)-theta)-cot theta tan(90^(@)

Evaluate: (sec 29^(@))/("cosec" 61^(@)) + 2 cot 8^(@) cot 17^(@) cot 45^(@) cot 73^(@) cot82^(@) - 3(sin^(2) 38^(@) + sin^(2) 52^(@)) + 4[cos theta sin(90^(@) - theta) + sin theta cos (90^(@) - theta)]

Evaluate : sin theta cos theta - (sin theta cos (90^(@) - theta) cos theta)/( sec (90^(@) - theta)) - (cos theta sin (90^(@) - theta) sin theta)/( cosec (90^(@) - theta))

(sin^(2) 20^(@) + sin^(2) 70^(@))/(cos^(2) 20^(@) + cos^(2) 70^(@)) + [ (sin (90^(@) - theta).sin theta)/(tan theta) + (cos (90^(@) - theta).cos theta)/(cot theta) ] .

tan^(2)(90^(@) - theta) - cosec^(2) theta =

tan^(2)(90^(@) - theta) - cosec^(2) theta =

Evaluate sin (50^(@) + theta) - cos (40^(@) - theta) + tan 1^(@) tan 15^(@) tan 20^(@) tan 70^(@) tan 65^(@) tan 89^(@) + sec (90^(@) - theta). cosec theta - tan (90^(@) - theta ) cot theta

Prove the following: (cos(90^(@)-theta)sec(90^(@)-theta)tan theta)/(cos ec(90^(@)-theta)sin(90^(@)-theta)cot(90^(@)-theta))+(tan(90^(@)-theta))/(cot theta)=2

Prove that : (i) sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1 (ii) sectheta" cosec"(90^(@)-theta)-tanthetacot(90^(@)-theta)=1 (iii) (sintheta*sec(90^(@)-theta)cot(90^(@)-theta))/("cosec"(90^(@)-theta)*costheta*tantheta)-(tan(90^(@)-theta))/(cottheta)=0 (iv) (1+sin(90^(@)-theta))/(cos(90^(@)-0))+(cos(90^(@)-theta))/(1+sin(90^(@)-0))=2"cosec"theta

Prove that : (i) sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1 (ii) sectheta" cosec"(90^(@)-theta)-tanthetacot(90^(@)-theta)=1 (iii) (sintheta*sec(90^(@)-theta)cot(90^(@)-theta))/("cosec"(90^(@)-theta)*costheta*tantheta)-(tan(90^(@)-theta))/(cottheta)=0 (iv) (1+sin(90^(@)-theta))/(cos(90^(@)-0))+(cos(90^(@)-theta))/(1+sin(90^(@)-0))=2"cosec"theta

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta