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" If "dx+dy=(x+y)(dx-dy)rArr log(x+y)=...

" If "dx+dy=(x+y)(dx-dy)rArr log(x+y)=

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If quad dx+dy=(x+y)(dx-dy)rArr log(x+y)=

If dx+dy=(x+y)(dx-dy) , then log(x+y) is equal to

(i) x(dy)/(dx)+y=log x

y log y (dx)/(dy) + x - log y =0

x^(y)=y^(x)rArr x(x-y log x)(dy)/(dx)=