[" For a projectile,the ratio of maximum "],[" theight reached to the square of time of "],[" flight is "(g=10m/sec^(2))]

For a projectile the ratio of maximum height reached to the square of flight time is (g=10 ms^(-2) )

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 ms^(-2))

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 ms^(-2))

A body is projected with an angle theta .The maximum height reached is h .If the time of flight is 4 sec and g=10m//s^(2) ,then the value of h is

" For a projectile the ratio of the square of the time of flight to its maximum height is "