[" Consider the reaction : "2N_(2)O_(4)rightleftharpoons4NO_(2)],[" If "-(d[N_(2)O_(4)])/(dt)=k" and "(d[NO_(2)])/(dt)=k'" then ":-]

For the reaction 2N_(2)O_(4)iff 4NO_(2) , given that (-d[N_(2)O_(4)])/(dt)=K " and "(d[NO_(2)])/(dt)=K , then

For the reaction 2N_(2)O_(4)iff 4NO_(2) , given that (-d[N_(2)O_(4)])/(dt)=K " and "(d[NO_(2)])/(dt)=K , then

Consider the reaction 2NO_(g)+O_(2(g))rarr 2NO_(2(g)) . If (d[NO_2])/(dt) = 0.052M//s then -(d[O_2])/(dt) will be

The rate of the reaction: 2N_(2)O_(5)rarr4NO_(2)+O_(2) can be written in three ways -(d[N_(2)O_(5)])/(dt)=k[N_(2)O_(5)] , (d[NO_(2)])/(dt)=k'[N_(2)O_(5)] ,(d[O_(2)])/(dt)=k''[N_(2)O_(5)] The relationship between k and k' and between k and k'' are-

Consider the following reaction, 2N_(2)O_(5)rarr4NO_(2)+O_(2),(d[NO_(2)] )/(dt)=k_(2)[N_(2)O_(5)] , (d[O_(2)])/(dt)=k_(3)[N_(2)O_(5)]" and "(d)/(dt)[N_(2)O_(5)]=k_(1) The relation between k_(1), k_(2) and k_(3) is

For the reaction 2N_(2)O_(5)rarr4NO_(2)+O_(2) the rate equation can be express as (d[N_(2)O_(5)])/(dt)=k[N_(2)O_(5) and (d[NO_(2)])/(dt)=k'[N_(2)O_(5)] k and k' are related as