The radius of the base of a right circular cone is r. It is cut by a plane parallel to the base at aheight h from the base. The slant height of the frustum is `sqrt(h^2+4/9r^2)`. Show that the volume of13the frustum is `13/27 pi r^2 h`.

The radius of the base ofa right circular cone is 'x'. It is cut by a plane parallel to the base at a height y from the base. The distance boundary of upper surface from the base of frustum is sqrt(y^(2)+(x^(2))/(9)) . Show that the volume of frustum is (13)/(27)pix^(2)ycu . units.

The diameter of the base of a right circular cone is 4 cm and its height 2sqrt(3) cm . The slant height of the cone is

The volume of a right circular cylinder is 2 pi r h sq- units, where r = radius of the base and h = height of the cylinder.

The ratio of the radius of the base and height of a right circular cone is 5:12 . If the volume of the cone be 314(2)/(7) c c then the slant height of the cone will be

Find the volume of a right-circular cone of base radius r and height h.

The slant height of a right circular cone is 10 cm and its height is 8 cm. It is cut by a plane parallel to its base passing through the midpoint of the height. Ratio of the volume of the cone to that of the frustum of the cone cut is

The radius of base of a cone is r and height is h. Find its volume.

The radius of base of a cone is r and height is h. Find its volume.