`1/6(4y+5)-2/3(2y+7)=3/2`

(4y+1)/(3)+(2y-1)/(2)-(3y-7)/(5)=(47)/(10)

((1) / (3) y ^ (2) - (4) / (7) y + 5) - ((2) / (7) y- (2) / (3) y ^ (2) +2 ) - ((1) / (7) y-3 + 2y ^ (2))

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Add the following algebraic expressions: 2,(2y)/3-(5y^2)/3+(5y^3)/2,-4/3+(2y^2)/3-y/2,(5y^3)/3+3y^2+3y+6/5

(1/3y^2-4/7 y+5)-(2/7y-2/3y^2+2)-(1/7y-3+2y^2)

Simplify: ((1)/(3)y^(2)-(4)/(7)y+11)-((1)/(7)y-3+2y^(2))-((2)/(7)y-(2)/(3)y^(2)+2)

Find the angle between the lines (5-x)/(3)=(y+3)/(-4) ,z=7 " and " (x)/(1) =(1-y)/(2)=(z-6)/(2)