A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is `mu` then
.

A block of mass M rests on an inclined plane. If the coefficient of friction between the block and the plane is mu then the block will slide down the plane under its own weight the angle of inclination is

A block of mass M rests on an inclined plane. If the coefficient of friction between the block and the plane is mu , then the block will slide down the plane under its own weight when the angle of inclination is

A block of mass m = 2kg is resting on a inclined plane of inclination 30^(@) The coefficient of friction between the block and the plane is mu = 0.5 what minimum force F (in newton) should be applied perpendicular to the plane on the block so that the does not slip on the plane?

A block of mass m is lying on an inclined plane. The coefficient of friction between the plane and the block is mu . The force (F_(1)) required to move the block up the inclined plane will be:-

A block of mass m is lying on an inclined plane. The coefficient of friction between the plane and the block is mu . The force (F_(1)) required to move the block up the inclined plane will be:-

A block of mass m is lying on an inclined plane. The coefficient of friction between the plane and the block is mu . The force (F_(1)) required to move the block up the inclined plane will be:-

A block of mass m is placed at rest on an inclination theta to the horizontal.If the coefficient of friction between the block and the plane is mu , then the total force the inclined plane exerts on the block is