" (ii) "asin((A)/(2)+B)=(b+c)sin(A)/(2)" ."quad [" Roorkee "69;B

In triangle ABC, (i) asin(A/2 + B) = (b+c) sin A/2

If a ,b ,c denote the lengths of the sides of a triangle opposite to angles A ,B ,C respectively of a A B C , then the correct relation among a ,b , cA ,Ba n dC is given by (b+c)sin((B+C)/2)=acos b. (b-c)cos(A/2)=asin((B-C)/2) c. (b-c)cos(A/2)=2asin((B-C)/2) d. (b-c)sin((B-C)/2)="a c o s"A/2

If A+B+C= pi and (sin 2 A + sin 2B + sin 2 C)/(sin A + sin B + sin C ) = lamda sin ((A)/(2)) sin ((B)/(2)) sin ((C )/(2)) , then the value of lamda must be

(x) (a sin(B-C))/(b^(2)-c^(2)) = (b sin (C-A))/(c^(2)-a^(2)) = (c sin(A-B))/(a^(2)-b^(2))

In triangle A B C ,a , b , c are the lengths of its sides and A , B ,C are the angles of triangle A B Cdot The correct relation is given by (a) (b-c)sin((B-C)/2)=acosA/2 (b) (b-c)cos(A/2)=asin((B-C)/2) (c) (b+c)sin((B+C)/2)=acosA/2 (d) (b-c)cos(A/2)=2asin(B+C)/2

In triangle A B C ,a , b , c are the lengths of its sides and A , B ,C are the angles of triangle A B Cdot The correct relation is given by (a) (b-c)sin((B-C)/2)=acosA/2 (b) (b-c)cos(A/2)=asin((B-C)/2) (c) (b+c)sin((B+C)/2)=acosA/2 (d) (b-c)cos(A/2)=2asin(B+C)/2

Consider a triangle ABC satisfying 2asin^(2)((C)/(2))+2csin^(2)((A)/(2))=2a+2c-3b Sin A , sin B , sin C are in