" 3) "int_(0)^(1)(dx)/([ax+b(1-x)]^(2))=

int_(0)^(1)(dx)/([ax+(1-x)b]^(2))=

int_(0)^(1)(dx)/([ax+(1-x)b]^(2))=

int_(0)^(1)(dx)/((1+x^(2))

int_(0)^(a)(dx)/((ax+a^(2)-x^(2)))

int_(0)^(a)(dx)/(sqrt(ax-x^(2)))

int_(0)^(1)(1+2x)dx

int_(0)^(1)(dx)/((x-a)(x-b))=

If int_(0)^(1) (e^(x))/( 1+x) dx = k , then int_(0)^(1) (e^(x))/( (1+x)^(2)) dx is equal to

Arrange the following according to their values in ascending order A) int_(0)^(1) sqrt(1-x^(2))dx B) int_(0)^(1) (1)/(sqrt(1-x^(2)))dx C) int_(0)^(1//sqrt(3))(1)/(1+x^(2))dx