सरल कीजिये ` i ^ ( n + 100) + i ^( n + 50 ) + i ^( n + 48) + i^(n + 46) `

1 + i^(2n) + i^(4n) + i^(6n)

i^(n) + i^(n+1) + i^(n + 2) + i^(n + 3)

Find the value of ( i^2 + n ) ( i^2 + n - 1 ) ( i^2 + n - 2 ) .......( i^2 + 1 )

For an positive integer n, prove that : i^(n) + i^(n+1) + i^(n+2) + i^(n+3) + i^(n+4) + i^(n + 5) + i^(n+6) + i^(n+7) = 0 .

If i= sqrt-1 and n is a positive integer , then i^(n) + i^(n + 1) + i^(n + 2) + i^(n + 3) is equal to

(I n (3)) (I n) = (I n (2)) ^ (2)

The value of 1/(i^n) + 1/(i^(n + 3)) + 1/(i^(n + 2)) + 1/(i^(n + 1)) is :

simplify : i^(n+100)+i^(n+50)+i^(n+48)+i^(n+46)

i ^n+i ^(n+1)+i ^(n+2)+i ^(n+3) (n∈N) is equal to