A parallel plate capacitor is charged by connecting is plates to the terminals of a battery. The battery remains connected to the condenser plates and a glass plate is interposed between the plates of the capacitor, then

A parallel plate capacitor is charged by connecting it to a battery. The battery is disconnected and the plates of the capacitor are pulled apart to make the separation between the plates twice. Again the capacitor is connected to the battery (with same polarity) then the potential difference between the plates increases when the plates are pulled apart (yes or not)

A parallel plate condenser is charged by connected it to a battery. The battery is disconnected and a glass slab is introduced between the plates. Then

A parallel plate condenser is charged by connected it to a battery. The battery is disconnected and a glass slab is introduced between the plates. Then

A parallel plate capacitor is charged by connecting it to a battery. Which of the following will remain constant if the distance between the plates of the capacitor is increased in this situation?

When a parallel plate capacitor is charged by connecting it across a battery then battery is disconnected. If one plate of capacitor is earthed and isolated then another plate is connected to earth and then isolated. What will be the final charge on the capacitor after this operation. Will it be less than, equal to or more than the initial charge? Explain why?