.Modulus of the function` z=(i-1)/(cos pi/3+i sin pi/3)` is

z=(1-i)/(cos(pi/3)+i sin(pi/3))

Write the complex number z = (i-1)/(cos pi/3 + i sin pi/3) in polar form.

z = (1+cos6 pi)+i sin6 pi

Convert the complex number z=(i-1)/(cos(pi)/(3)+i sin(pi)/(3)) in the polar form.

if z = cos ""pi/4 + i sin""pi/6 then

The numerical value of (where i = sqrt-1 ) (cos pi/10 + i sin pi/10)(cos 2pi/10 + i sin 2pi/10) xx (cos 3pi/10 + i sin 3pi/10) (cos 4pi/10 + i sin 4pi/10) = ..........

If i=sqrt(-1) then (cos(pi/3)+i sin(pi/3))^3=

The continued product of the four values of (cos((pi)/(3))+i sin((pi)/(3)))^((3)/(4)) is