Recommended Questions
- sqrt 5 ಒಂದು ಅಭಾಗಲಬ್ಧ ಸಂಖ್ಯೆ ಎಂದು ಸಾಧಿಸಿ.
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- (sqrt(5)-1)/(sqrt(5)+1)+(sqrt(5)+1)/(sqrt(5)-1)=a+bsqrt(5)
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- Simplify ((sqrt(5)-sqrt(3))(sqrt(5)+sqrt(3)))/((sqrt(5)+2)+(2-sqrt(5))...
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- (2)/(sqrt(3)+sqrt(5))+(5)/(sqrt(3)-sqrt(5))=x sqrt(3)+y sqrt(5)
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- (sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))+(sqrt(5)-sqrt(3))/(sqrt(5)+sqrt(3)...
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- দেখাও যে, (sqrt 5+sqrt 3)/(sqrt 5-sqrt 3)-(sqrt 5-sqrt 3)/(sqrt 5+sqrt...
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- sqrt( 5 sqrt( 5 sqrt( 5 sqrt( 5 sqrt( 5 sqrt(5) ) ) ) ) ) का मान है
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- sqrt(5 + sqrt(5 + sqrt(5 + sqrt(5 +)......)))prop = ?
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- sqrt(5 sqrt(5 sqrt(5 sqrt(5)))) = ?
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