`CH_(3)-O-CH_(3)` is:

Options

A. Lewis acid
B. Arrhenius acid
C. Lewis base
D. Bronsted acid

Answer

To determine the classification of the compound \( CH_3OCH_3 \) (dimethyl ether), we will analyze its structure and properties step by step.

### Step 1: Identify the Structure
The compound \( CH_3OCH_3 \) consists of two methyl groups (\( CH_3 \)) attached to an oxygen atom. The structure can be represented as follows:

```
H H
\ /
C
/ \
H O H
\ /
C
/ \
H H
```

### Step 2: Analyze the Functional Groups
In this structure, the oxygen atom has two lone pairs of electrons. The presence of these lone pairs is crucial for determining the compound's behavior in chemical reactions.

### Step 3: Determine Lewis Acid-Base Behavior
- **Lewis Base**: A Lewis base is defined as a species that can donate an electron pair. Since the oxygen in \( CH_3OCH_3 \) has two lone pairs, it can donate one of these pairs to form a bond with a Lewis acid (an electron pair acceptor).
- **Lewis Acid**: A Lewis acid is a species that can accept an electron pair. Since \( CH_3OCH_3 \) does not have the ability to accept electron pairs in this context, it cannot be classified as a Lewis acid.

### Step 4: Evaluate Arrhenius and Bronsted Acid Behavior
- **Arrhenius Acid**: An Arrhenius acid is a substance that increases the concentration of \( H^+ \) ions in solution. \( CH_3OCH_3 \) does not release \( H^+ \) ions, so it does not qualify as an Arrhenius acid.
- **Bronsted Acid**: A Bronsted acid is defined as a proton donor. Again, \( CH_3OCH_3 \) does not donate protons, so it cannot be classified as a Bronsted acid.

### Conclusion
Based on the analysis, \( CH_3OCH_3 \) (dimethyl ether) is classified as a **Lewis Base** because it has lone pairs of electrons that can be donated.

### Final Answer
\( CH_3OCH_3 \) is a **Lewis Base**.

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