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The half-life of a radioactive substance...

The half-life of a radioactive substance is `48` hours. How much time will it take to disintegrate to its `(1)/(16) th` parts ?

A

32 days

B

32 hrs

C

48 hrs

D

16 hrs

Text Solution

Verified by Experts

The correct Answer is:
b
75% decay takes place in `t_(3//4)` (3 / 4 th life)
`t_(3//4) = 2t_(1//2) = 2 xx 16 = 32` hrs
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