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.(7)^(14)N is attacked by doubly charged...

`._(7)^(14)N` is attacked by doubly charged helium ion, it emits a proton and:

A

`._(9)^(18)F`

B

`._(8)^(17)O`

C

`._(8)^(18)O`

D

`._(9)^(19)F`

Text Solution

Verified by Experts

The correct Answer is:
b

`._(7)^(14)N + ._(2)^(4)He to ._(8)^(17)O + ._(1)^(1)H`
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