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Calculate the ratio of (N)/(N(0)) after ...

Calculate the ratio of `(N)/(N_(0))` after n hour has passed for a radioactive material of half life 47.2 seconds.

Text Solution

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`lambda t = 2.303 log_(10) (N_(0))/(N)`
`(0.693)/(47.2) xx (60 xx 60)/(2.303) = log_(10) (N_(0))/(N)`
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