The isotope .(92)^(235)U decays in a num...

The isotope `._(92)^(235)U` decays in a number of steps to an isotope of `._(82)^(207)Pb`. The groups of particle emitted in this process will be:

A

`4 alpha, 7 beta`

B

`6 alpha, 4 beta`

C

`7 alpha, 4 beta`

D

`10 alpha, 8 beta`

Text Solution

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The correct Answer is:

c

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