Radioactivity of a radioactive element remains `1//10` of the original radioactivity after `2.303` seconds. The half life period is

Options

A. 2.303
B. 0.2303
C. 0.693
D. 0.0639

Answer

c

Explanation

`lambda = (2.303)/(t) log_(10) (a)/(a - x)`
or `lambda = (2.303)/(2.303) log_(10) (1)/(1//10) =1, T = (0.693)/(lambda) = 0.693`