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A positron is emitted from .(11)Na^(23) ...

A positron is emitted from `._(11)Na^(23)` . The ratio of the atomic mass and atomic number of the resulting nuclide is

A

22/10

B

22/11

C

23/10

D

23/12

Text Solution

Verified by Experts

The correct Answer is:
c
`._(1)^(1) H to ._(0)^(1)n + underset("Positron")(._(+1)^(0)e)`
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