Bombardment of aluminium by `alpha-"particle"` leads to its artificial disintegration in two ways, `(i) and (ii)` as shown.
Products `X,Y` and `Z` respectively, are

Options

A. proton, neutron, positron
B. neutron, positron, proton
C. proton, positron, neutron
D. positron, proton, neutron

Answer

a

Explanation

(i) `._(13)^(27)Al + ._(2)^(4)He to ._(14)^(30)Si + ._(1)^(1)H`
`:.` X = Proton `(._(1)^(1)H)`
(ii) `._(13)^(27)Al + ._(2)^(4)He to ._(15)^(30)P ._(0)^(1)n`
`:.` Y = Neutron `(._(0)^(1)n)`
(iii) `._(15)^(30) P to ._(14)^(30)Si + ._(+1)^(0)e`
`:.`Z = Position `(._(+1)^(0)e)`