Isodiapheres are the atoms of two elements having same values of:

Options

A. p/n
B. (p-n)
C. (n - p)
D. `n xx p`

Answer

c

Explanation

Isodiapheres are formed by `alpha` decaya
`._(Z)^(M)A - ._(2)^(4)He to ._(Z-2)^(M-4)B`
`(n - p)` in `._(Z)^(M)A = (M - Z) - Z = (M - 2Z)`
`(n - p)` in `._(Z - 2)^(M - 2)B = {(M - 4) - (Z - 2)} - (Z - 2)`
`(M - Z - 2} - Z + 2`
`= (M - 2Z)`
`:. (n - p)` of isodiapheres are same.