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.(13)Al^(27) is a stable isotope. .(13)A...

`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

A

`alpha`-emission

B

`beta`-emission

C

positron emission

D

proton emission

Text Solution

Verified by Experts

The correct Answer is:
b
Number of neutrons will be reduced by `beta`-decay.
`._(0)^(1)n to ._(1)^(1)H + ._(-1)^(0)e` + Antineutrino + Energy
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