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For a radioactive element, a graph of lo...

For a radioactive element, a graph of log N against time has a slope equal to:

A

`2.303 lambda`

B

`+ (lambda)/(2.303)`

C

`- (lambda)/(2.303)`

D

`-2.303 lambda`

Text Solution

Verified by Experts

The correct Answer is:
c
log `N_(0) - log N = (lambda t)/(2.303)`
`log N = ((-lambda)/(2.303)) t + log N_(0)`
`Y = Mx + C`
`:.` Slope (M) `= (-lambda)/(2.303)`
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