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Uranium .(92)U^(238) decayed to .(82)Pb^...

Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))`
`t_(1//2)` of `U^(238) = 4.5 xx 10^(9)` years
The analysis of a rock shows the relative number of `U^(238)` and `Pb^(206)` atoms `(Pb//U = 0.25)` The age of rock will be

A

`(2.303)/(0.693) xx 4.5 xx 10^(9) log 1.25`

B

`(2.303)/(0.693) xx 4.5 xx 10^(9) log 0.25`

C

`(2.303)/(0.693) xx 4.5 xx 10^(9) log 4`

D

`(2.303)/(4.5 xx 10^(9)) xx 0.693 log 4`

Text Solution

Verified by Experts

The correct Answer is:
a
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