Home
Class 12
CHEMISTRY
Radioactive decay follows first-order ki...

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are `tau = 1// lambda` and `t_(1//2) = 0.693//lambda`. Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after `n` half lives of radioactive elements can be calculated using the relation:
`N = N_(0) ((1)/(2))^(n)`
The rate of radioactive decay is a)Independent of time b)Independent of temperature c)Dependent on catalyst d)Dependent on the amount of elementsd not yet decayed

A

independent of time

B

independent to temperature

C

dependent of catalyst

D

dependent on the amount of element not yet decayed

Text Solution

Verified by Experts

The correct Answer is:
b,d
Promotional Banner

Topper's Solved these Questions

  • RADIOACTIVITY AND NUCLEAR TRANSFORMATION

    OP TANDON|Exercise psg-IX|5 Videos

  • RADIOACTIVITY AND NUCLEAR TRANSFORMATION

    OP TANDON|Exercise SECTION - I|10 Videos

  • RADIOACTIVITY AND NUCLEAR TRANSFORMATION

    OP TANDON|Exercise psg-VII|5 Videos

  • ORGANIC COMPOUNDS CONTAINING NITROGEN

    OP TANDON|Exercise Single integer|8 Videos

  • SATURATED ALIPHATIC HYDROCARBONS

    OP TANDON|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|7 Videos

Similar Questions

Explore conceptually related problems

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Select the correct relation.

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Which "is"//"are" true about the decay cosntant?

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Amount of radioactive elements (activity) decreases with passage of time as

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) Half life of .^(60)Co is 5.3 years, the time taken for 99.9% decay will be

The decay constant (lambda) for radioactive decay is independent of

The half line of a radioactive element is 2n year. The fraction decayed in n year.

A fraction f_1 of a radioactive sample decays in one mean life, and a fraction f_2 decays in one half life. Then

Given that radioactive species decays according to the exponential law N=N_(0) e^(-lambda t) . The half life of the species is