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Radioactive decay follows first-order ki...

Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are `tau = 1// lambda` and `t_(1//2) = 0.693//lambda`. Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after `n` half lives of radioactive elements can be calculated using the relation:
`N = N_(0) ((1)/(2))^(n)`
Select the correct relation. a)`t_(1//2) = (0.693)/(lambda)` b)`tau = (1)/(lambda)` c)`tau = 1.44 xx t_(1//2)` d)`tau = (t_(1//2))/(0.693)`

A

`t_(1//2) = (0.693)/(lambda)`

B

`tau = (1)/(lambda)`

C

`tau = 1.44 xx t_(1//2)`

D

`tau = (t_(1//2))/(0.693)`

Text Solution

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The correct Answer is:
a,b,c,d
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