If `f'(0)=3` then `lim_(x->0)(x^2)/(f(x^2)-6f(4x^2)+5f(7x^2)=`

If f^(1)(0)=-3 then Lt_(x to 0) (x^(2))/(f(x^(2))-6.f(4x^(2))+5.f(7x^(2)))=

If the normal to differentiable curve y = f(x) at x = 0 be given by the equation 3x-y + 3 = 0 , then the value of lim_(x->0) x^2(f(x^2)-5f(4x^2)+ 4f(7x^2)) is

If f(0)=3 then Lt_(x rarr oo)(x^(2))/(f(x^(2))-6,f(4x^(2))+5.f(7x^(2)))

If the normal to y=f(x) at (0, 0) is given by y-x =0, then lim_(x to 0)(x^(2))/(f(x^(2))-20f(9x^(2))+2f(99x^(2))) , is

If the normal to y=f(x) at (0, 0) is given by y-x =0, then lim_(x to 0)(x^(2))/(f(x^(2))-20f(9x^(2))+2f(99x^(2))) , is

If the normal to y=f(x) at (0, 0) is given by y-x =0, then lim_(x to 0)(x^(2))/(f(x^(2))-20f(9x^(2))+2f(99x^(2))) , is

If the normal to differentiable curve y=f(x) at x=0 be given by the equation 3x-y+3=0, then the value of lim_(x rarr0)(x^(2))/(f(x^(2))-5f(4x^(2))+4f(7x^(2))) is

If the equation of the normal to the curve y=f(x) at x =0 is 3x-y+3=0 then the value of lim_(x rarr0)(x^(2))/({f(x^2)-5f(4x^(2))+4f(7x^(2))}) is

If the equation of the normal to the curve y=f(x) at x=0 is 3x-y+3=0 then the value of lim_(xrarr0) (x^(2))/({f(x^(2))-5f(4x^(2))+4f(7x^(2))}) is