An electron is revolving in a circular path of radius `2xx10^(-10)` m with a speed of `3xx10^(6)` m/s. The magnetic field at the centre of circular path will be-

An electron revolves in a circle of radius 0.4 Å with a speed of 10^(5)m//s . The magnitude of the magnetic field produced at the centre of the circular path due to the motion of the electron in W//m^(2) is

The electron in a hydrogen atom moves in circular orbit of radius 5xx10^(-11)m with a speed of 0.6pixx10^(6)m//s then

The electron in a hydrogen atom moves in circular orbit of radius 5xx10^(-11)m with a speed of 0.6pixx10^(6)m//s then

An alpha particle moves along a circular path of radius 1.0 xx 10^(-10)m with a uniform speed of 2 xx 10^(6) m/s calculate the magnetic field produced at the centre of orbit.

An alpha particle moves along a circular path of radius 2Å with a uniform speed of 2xx10^6ms^-1 . Calculate the magnetic field set up at the center of circular path.

A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is

If an electron is revolving in a circular orbit of radius 0.5A^(@) with a velocity of 2.2xx10^(6)m//s . The magnetic dipole moment of the revolving electron is

A particle having charge 100 times that of an electron is revolving in a circular path by radius 0.8 m with one rotation per second. The magnetic field produced at the centre is,